Mathematics, 20.12.2019 17:31, julk89

In δjkl, k = 3.7 cm, ∠k=15° and ∠l=41°. find the length of j, to the nearest 10th of a centimeter.

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In δjkl, k = 3.7 cm, ∠k=15° and ∠l=41°. find the length of j, to the nearest 10th of a centimeter....