2x+3y=4

and

2x-5y=-12

solve the given system by elimination and justify each step. which procedure would not result in a system with a pair of opposite terms?

a) multiply both sides of 2x + 3y = 4 by −1 and use the other equation to produce a system with a pair of opposite terms. this is an application of the multiplicative property of equality.

b) multiply both sides of 2x − 5y = −12 by −1 and use the other equation to produce a system with a pair of opposite terms. this is an application of the multiplicative property of equality.

c) multiply both sides of 2x − 5y = −12 by 3 and multiply both sides of 2x + 3y = 4 by 5 to produce a system with a pair of opposite terms. this is an application of the multiplicative property of equality.

d) multiply both sides of 2x − 5y = −12 by −3 and multiply both sides of 2x + 3y = 4 by 5 to produce a system with a pair of opposite terms. this is an application of the multiplicative property of equality.

Option D

Step-by-step explanation:

we have

-----> equation A

-----> equation B

Solve the system by elimination

Multiply both sides equation A by -1

-----> equation C

Adds equation C and equation B

Find the value of x

substitute the value of y in either equation

The solution is the point (-1,2)

In this problem Option A,B and C are correct

The option D not result in a system with a pair of opposite terms

because

Multiply both sides of equation B by -3

 -----> equation C

Multiply both sides of equation A by 5

----> equation D

so

equation C and equation D not have a pair of opposite terms

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!

your answer   is c

step-by-step explanation: