Through (1,3) perpendicular to 3x+2y=5

The equation of line passing through points (1 , 3) and perpendicular to given line is  y = x +

Step-by-step explanation:

Given as :

The equation of line is 3 x + 2 y = 5

Or , 2 y = - 3 x + 5

Or , y = x +

Another line is passing through point (1 , 3) and perpendicular to given line equation

Now, From standard line equation

i.e y = m x + c

where m is the slope of the line and c is the y-intercept

Now, comparing the given line equation with standard line equation

i.e y = x +

So, The slope of line = m =  

According to question

Another line is perpendicular to the given line

So, for perpendicular property, The product of the lines = - 1

Let the sloe of another line = M

So, m × M = - 1

∴ M =

Or. M =

I.e M =

So, the slope of another line = M =

Now, equation of line passing through slope M and point (1 , 3)

I.e equation of line in slope-points

So, y - = m ( x - )

or, y - 3 = ( ) × ( x - 1 )

Or, 3 × (y - 3) = 2 × (x - 1)

Or, 3 y - 9 = 2 x - 2

Or, 3 y = 2 x - 2 + 9

Or, 3 y = 2 x + 7

∴ y = x +

So, The equation = y = x +

Hence, The equation of line passing through points (1 , 3) and perpendicular to given line is  y = x +  Answer

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

12

step-by-step explanation:

a triangle's   full angle is 180 degrees so 180 - 156 = 24. 24/2=12