An equation of an ellipse is given. y2 = 1 − 3x2 (a) find the vertices, foci, and eccentricity of the ellipse. vertex (x, y) = (smaller y-value) vertex (x, y) = (larger y-value) focus (x, y) = (smaller y-value) focus (x, y) = (larger y-value) eccentricity (b) determine the length of the major axis. determine the length of the minor axis.

Step-by-step explanation:

Given

therefore it is a vertical ellipse

thus a=1

eccentricity of Ellipse

Focii are and

thus focii are &

(b) Length of major axis

length of minor axis

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

.25

step-by-step explanation: