Henry deposited $1,000 in a new savings account. he made no other deposits or withdrawals. after 6 months the interest was computed at an annual interest rate of 6.5%?

The interest that is computed in the account is $31.98

Step-by-step explanation:

Given as :

The principal amount deposited into saving account = p = $1000

The rate of interest applied = r = 6.5%

The amount is deposited for time period = t = 6 months = 0.5 year

Let the Amount in account after 6 months = $A

And Let The interest amount that is gained = $x

Now, From Compound Interest method

Amount = principal ×

Or, A = p ×

Or, A = $1000 ×

Or, A = $1000 ×

Or, A = $1000 × 1.03198

∴ A = $1031.98

So, The Amount in account after 6 months = A = $1031.98

Now, Again

Interest = Amount - Principal

Or, x = A - p

Or, x = $1031.98 - $1000

∴   x = $31.98

So, The interest that is computed in the account = x = $31.98

Hence,The interest that is computed in the account is $31.98 Answer

idk bring the function back   im not smart

step-by-step explanation:

a) $ 9.50

b) 17

c) y-intercept (0, 12). this is the initial amount of money that joe had prior to playing any game.

d) x-intercept ( 24, 0). this is the number of games that joe will play before he depletes the initial amount of money that he had.

e) slope is -0.5. joe's balance will reduce by 0.5 for every game that he plays.

f)

domain; [0,24]

range; [0,12]

g) x + 2y = 24

step-by-step explanation:

a)

if joe plays 5 games, this will imply that x = 5. substitute x = 5 in the equation and solve for y;

y = -.50x + 12

y = -0.50(5) + 12

y = 9.50

b)

if joe leaves the arcade with $3.50, this will mean that y = 3.50. plug in y = 3.50 in the given equation and solve for x;

y = -.50x + 12

3.50 = -0.50x + 12

0.50x = 12 - 3.50

0.5x = 8.5

x = 17

c)

the function given is   y = -.50x + 12.

the y-intercept is the point where the graph of this function will intersect the y-axis. at this point, the value of x is usually 0. plug in x = 0 in the given equation and determine y;

y = -0.50(0) + 12

y = 12

the y-intercept is thus (0, 12). this is the initial amount of money that joe had prior to playing any game.

d)

the x-intercept refers to the point where the graph of a function intersects with the x-axis. at this point, the value of y is 0. substitute y = 0 in the given equation and solve for x;

0 =   -.50x + 12

0.5x = 12

x = 24

x-intercept ( 24, 0). this is the number of games that joe will play before he depletes the initial amount of money that he had.

e)

the slope of the given equation is -0.5. the equation has been given in slope-intercept form. thus the slope is simply the coefficient of x.

joe's balance will reduce by 0.5 for every game that he plays. this is the interpretation of the slope.

f)

domain is the set of x values for which the function is real and defined. the domain will thus be; [0,24]. this will restrict the balance to only assume positive values.

on the other hand, the range is the set of y values for which a function is real and defined. the range in our case will be [0,12]. joe can have between $0 and $12 balance.

g)

the standard form of the equation of a straight line is;

ax + by = c

where a, b, and c are integers.

our equation is given as;

y = -.50x + 12

re-writing the equation we have;

0.5x + y = 12

divide all through by 0.5;

x + 2y = 24