If f(x) = x2 − 6x + 19, complete the square and determine the minimum or maximum value of the function.
a) f(x) = (x + 3)2 + 28 and f(x) has a maximum value f(3) = 28.
b) f(x) = (x + 3)2 + 28 and f(x) has a minimum value f(3) = 28.
c) f(x) = (x − 3)2 + 10 and f(x) has a maximum value f(3) = 10.
d) f(x) = (x − 3)2 + 10 and f(x) has a minimum value f(3) = 10. eliminate

D

Step-by-step explanation:

(Using the formula in my attachment)

x^2 − 6x + 19

(x - 3)^2 = x^2 - 6x + 9

9 - e = 19

e = -10

(x - 3)^2 - e

(x - 3)^2 - - 10

(x - 3)^2 + 10

when x - 3 = 0, x = 3

Subsitute 3 into the equation

(3 - 3)^2 + 10

0 + 10

Minimum (3,10) in this case f(3) = 10

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58