Cloud seeding has been studied for many decades as a weather modification procedure (for an interesting study of this subject, see the article in technometrics, "a bayesian analysis of a multiplicative treatment effect in weather modification," 1975, vol. 17, pp. 161–166). the rainfall in acre-feet from 20 clouds that were selected at random and seeded with silver nitrate follows: 18.0, 30.7, 19.8, 27.1, 22.3, 18.8, 31.8, 23.4, 21.2, 27.9, 31.9, 27.1, 25.0, 24.7, 26.9, 21.8, 29.2, 34.8, 26.7, and 31.6. a) can you support a claim that mean rainfall from seeded clouds exceeds 25 acre-feet? use α =

1     sepan

2     encuentren

3     tenga

4     hable

5   parezca

6   llegue

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

150.6

all i did was i multiplied 5.02 by 30