From the top of a vertical cliff 50 m high, the angle of depression of an object that is level with the base of the cliff is 70°. how far is the object from the base of the cliff?

The distance of the object from the base of cliff is 18.24 meters

Step-by-step explanation:

Given as :

The height of the vertical cliff = h = 50 meters

The distance of the object from the base of cliff = x meters

Let The angle of depression of object that level with cliff base = Ф = 70°

Now, from figure

Tan angle =

I.e TanФ =

Or, TanФ =

Or, Tan 70° =

Or, 2.74 =

∴ x =  

I,e x = 18.24 meters

So, The distance of the object from the base of cliff = x = 18.24 meters

Hence,The distance of the object from the base of cliff is 18.24 meters Answer

answer: b.48 for

step-by-step explanation:

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75