Solve the system by substitution.
2.5x-3y=-13
3.25x-y=-14

x=-4

y=1

Step-by-step explanation:

For the given system of equations,

2.5x-3y=-13eqn(1)

3.25x-y=-14eqn(2)

We first make y the subject of eqn (2)

This implies that,

y=3.25x+14eqn(3)

We substitute eqn (3) into eqn (1)

2.5x-3(3.25x+14)=-13

2.5x-9.75x-42=-13

-42+13=9.75x-2.5x

-29=7.25x

Dividing through by 7.25, we obtain

x=-4

We now put the value of x into eqn (2)

3.25(-4)-y=-14

This implies that,

-13+14=y

y=1

answer: i literally just answered this question but they want me to do it again

step-by-step explanation:

- (2, -7)

- lines r and s and lines t and u must be parallel