Find all the zeros of the equation. -x^3-3x^2=6x+4

The zeros of given expression is -1, and

Step-by-step explanation:

Given expresssion is

To find zeros of given expression we have to equate the expression to zero.

ie.,

By using synthetic division

-1  |  1    3    6    4

    |  0   -1   -2   -4

    |________________

       1    2   4    0

Therefore (x+1) is a  zero

Now the quadratic equation is

For quadratic equation  we have

Here a=1 ,b=2 and c=4 now substitute the values

where

Therefore  and

Therefore the zeros are -1, and

good luck!

cutie~

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb