Coo
1. abcd is a parallelogram. the diagram is not drawn to scale. if mzcda = 125°, then mzdcb
(1 point)
m
mm
125°
65°
55°
120°

Therefore

m∠ DCB is 55°

Step-by-step explanation:

Given:

ABCD is a parallelogram. The diagram is not drawn to scale.

m∠CDA = 125°,

To FInd

m∠DCB  = ?

Solution:

ABCD is a parallelogram.

AD || BC .......{opposite sides of a parallelogram are parallel}

∴∠CDA+∠DCB = 180°{SUM of the interior angles between parallel are supplementary}

substituting the values we get

Therefore

m∠ DCB is 55°

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

∠cbe and ∠deb are same-side interior angles.

i took the test