In slope-intercept form, what is the equation of the line passing through the points (-4.26) and (6-4)?
y=-3x - 14
y = 3x - 14
y = -3x - 14
y=-x
-2

y=-3x+14

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-4-26)/(6-(-4))

m=-30/(6+4)

m=-30/10

m=-3

y-y1=m(x-x1)

y-26=-3(x-(-4))

y-26=-3(x+4)

y=-3x-12+26

y=-3x+14

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.