The graph of a quadratic function is shown. check all of the following statements that are true of the function.

a < 0

the vertex is (1,2)

the axis of symmetry is y =2

x = 2 is a zero of the function

(1,2) is a minimum

a < 0

The vertex is (1,2)

Step-by-step explanation:

Looking at the graph

we have a vertical parabola open downward

The leading coefficient is negative

The vertex is a maximum

The vertex is the point (1,2)

The axis of symmetry is equal to the x-coordinate of the vertex, so the axis of symmetry is x=1

The y-intercept is the point (0,1)

The function has two real solutions (zeros of the function) one positive and one negative

The positive zero of the function is greater than 2

The negative zero of the function is greater than -1

Verify each statement

case 1) a < 0

The statement is true

Because the parabola open downward

case 2) The vertex is (1,2)

The statement is true

The vertex in this problem is the maximum of the function

case 3) The axis of symmetry is y =2

The statement is false

Because the axis of symmetry is x=1

case 4) x = 2 is a zero of the function

The statement is false

Because the positive zero of the function is greater than 2

case 5) (1,2) is a minimum

The statement is false

Because the vertex in this problem is a maximum

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

answer: your gay

step-by-step explanation:

you dont know math