What is the equation of the line which

includes the points (2, 4) and (14, –2)?

a. y=5x−12

b. y=−12x−5

c. y=−12x+5

d. y=−2x+5

The equation of the line is y = (-1/2)x + 5

Step-by-step explanation:

First of all, have to find gradient using the formula above :

(2,4) & (14,-2)

m = (-2-4) / (14-2)

= -6 / 12

= -1/2

Second, using y = mx + b as b is a constant and is a y-intercept. Using any of these 2 coordinates to find the value of b with given gradient :

y = mx + b

Let y=4 & x=2

4 = (-1/2)(2) + b

b = 4 + 1

= 5

Lastly, put the value of gradient and y-intercept into the equation :

y = mx + b

Let m=-1/2 & b=5

y = (-1/2)x + 5

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.