Which are real zeroes of this function? x3 + 2x2 – 9x – 18.
a. 1, 2, 3
b. 3, -3, 2
c. 2, 3, -6
d. 1, -1, 18
e. -2, 3, -3

The real zeros of function are (-2, 3, -3)

Given function is:

To find the zeroes of the function, we just need to evaluate the values and check if the function/expression tends to 0.

Let

On grouping the terms we get,

Taking as common term from first two terms and "9" as common term from last two terms,

Taking (x + 2) as common term,

We know that,

Applying the above identity,

We equate the function to 0 , to find the zeros of polynomial function

(x + 3)(x - 3)(x + 2) = 0

Therefore zeros are:

x + 3 = 0

x - 3 = 0

x + 2 = 0

Thus zeros are (-2, 3, -3) Option E is correct

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

most likely the answer is a.

alice wins if a total of 5 is rolled. finn wins if a total of 9 is rolled.