What are the exact solutions of x2 − x − 4 = 0, where x equals negative b plus or minus the square root of b squared minus 4 times a times c all over 2 times a?

a: x = the quantity of negative 1 plus or minus the square root of 15 all over 2
b: x = the quantity of 1 plus or minus the square root of 15 all over 2
c: x = the quantity of 1 plus or minus the square root of 17 all over 2
d: x = the quantity of negative 1 plus or minus the square root of 17 all over 2

The answer is option C: x = the quantity of 1 plus or minus the square root of 17 all over 2

Step-by-step explanation:

The general form of the quadratic equation is ax² + bx + c = 0

The general solution of the quadratic equation is:

The given equation is x² − x − 4 = 0

So, a = 1 , b = -1 and b = -4

Substitute with a , b and c at the formula of the general solution.

The solution of the given equation =

Comparing the solution with the given options

So, the answer is option C: x = the quantity of 1 plus or minus the square root of 17 all over 2

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4

step-by-step explanation:

infinity is the answer