Apopcorn company builds a machine to fill 1 kg bags of popcorn. they test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams. 1.) fill out the normal distribution curve for this situation. 2.) what percentage of people would receive a bag that had a weight greater than 1115 grams?

Step-by-step explanation:

Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.

i.e. Sample mean = 1040 and

Sample std dev s = 25 gm

Sample size n = 100

Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm

Normal curve would be with mean 1040 and std deviatin 25

b) P(X>1115)

= 1-0.9987

=0.0013

i.e. 0.13% would receive a bag that had a weight greater than 1115 grams

518,400

step-by-step explanation:

the area is multiplying all the given measurements together.

40 * 18 * 30 * 24 = 518,400