Candidate a is facing two opposing candidates in a mayoral election. in a recent poll of 300 residents, 98 supported candidate b and 58 supported candidate c. construct a 95% confidence interval on the population proportion for the support of candidate a in the following election. [0.4781, 0.4819] [0.4235, 0.5365] [0.3942, 0.5658] [0.4057, 0.5543]

[0.4235, 0.5365]

Step-by-step explanation:

Data given and notation  

n=300 represent the random sample taken    

X=300-98-58=144 represent the people that support the candidate A in the sample

estimated proportion of people that support the candidate A in the sample

represent the significance level

Confidence =0.95 or 95%

p= population proportion of people that support the candidate A.

Confidence interval

The confidence interval would be given by this formula

For the 95% confidence interval the value of and , with that value we can find the quantile required for the interval in the normal standard distribution.

And replacing into the confidence interval formula we got:

And the 95% confidence interval would be given (0.4235;0.5365).

i pretty sure it is