The arrival time of my usual morning bus (b) is normally distributed, with a mean eta at 8: 00 am, and a standard deviation of 4 minutes. my arrival time (a) at the bus stop is also normally distributed, with a mean eta at 7: 50 am, and a standard deviation of 3 minutes. (a) with what probability can i expect to catch the bus? (hint: what is the distribution of the random variable x = a – b, and what must be true about x in the event that i catch the bus? ) (b) on average, how much earlier should i arrive, if i expect to catch the bus with 99% probability?

the answer is 1 becuz if it were 1.0 that would rip apart the entire so ya. : )

~potato.

copyright potato 2019.

d. $180

step-by-step explanation:

if the dimensions of the room is 9ft by 12 ft, we have the area of the floor as,

so the area of the floor is 108 square feet, converting that into square yards we get,

the cost of carpet is $15 per square yard, therefore the cost of carpet for 12 square yards is,

hence, the cost of carpet is $180.

assuming the dimensions of the room be,

15 ft by 12 ft

so, the area of the floor of that room is,

we can convert 180 square feet into square yards, we know that,

1 sq ft = 0.111 sq yard

so, 180 square feet is,

so the area of floor is 20 square yards.

now, the cost of carpet is 15 dollars per square yard, therefore the cost of carpet for 20 square yards is,

so, it will cost $300.

using pemdas, (order of operations) you'll see the answer is 24.