The average annual salary for employees in a store is $50,000. it is given that the population standard deviation is $5,000.

suppose that a random sample of 70 employees will be selected from the population. what is the value of the standard error of the average annual salary?

round your answer to the nearest integer.

Standard error of the average annual salary SE = $597.6

Step-by-step explanation:

Given;

Standard deviation = r = $5,000

Number of samples = n = 70

Mean = $50,000

To derive the standard error of mean SE. It is given as

SE = r/√n

SE = $5,000/√70

SE = $5,000/8.3666

SE = $597.6

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )