On his way to work every morning, bob first takes the bus from his house, exits near his workplace, and walks the remaining distance. his time spent on the bus (x) is a random variable that follows a normal distribution, with mean µ = 20 minutes, and standard deviation  = 2 minutes, i. e., x ~ n(20, 2). likewise, his walking time (y) is also a random variable that follows a normal distribution, with mean µ = 10 minutes, and standard deviation  = 1.5 minutes, i. e., y ~ n(10, 1.5). find the probability that bob arrives at his workplace in 35 minutes or less. [hint: total time = x + y ~ recall the "general fact" on page 4.1-13, which is true for both discrete and continuous random variables.]

idk

step-by-step explanation: i just don't

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

the correct answers i think are b. and d.

give me brainliest if it is correct!