Ineed i need to get this done asap!

By Angle-Angle i.e. AA theorem we can say that Δ KOM and Δ LNM are similar.

Step-by-step explanation:

See the attached diagram.

We have to prove that Δ KOM and Δ LNM are similar.

Now, radius OK and NL are perpendicular to OM and hence,  

∠ KOM and ∠ LNM are right angles i.e. 90°.

Now, between Δ KOM and Δ LNM,

(i) ∠ KOM = ∠ LNM = 90°

(ii) ∠ M is a common angle.

Hence, by Angle-Angle i.e. AA theorem we can say that Δ KOM and Δ LNM are similar. (Answer)

no problobm

step-by-step explanation:

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )