If a fair coin is tossed five times, which of the following ordered sequence of heads (h) and tails (t), if any, is most likely to occur? a. h t h t t b. t h h h h c. h t h t h d. only sequences (a) and (c) are equally likely. e. all of the above sequences are equally likely.

Option E.

Step-by-step explanation:

If A and B are two events and P(A)>P(B), then event A is more likely to occur than event B.

It is given that a fair coin is tossed five times. It means

Probability of  H T H T T is

Similarly probability of T H H H H and H T H T H is .

Since all events have same probability, therefore all of the above sequences are equally likely.

Thus, the correct option is E.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

13

step-by-step explanation:

divide the cost of the total of sodas you bought by the cost of one soda, for example:

$24.57 divided by $1.89 is 13 which means you bought 13 sodas