Look at the right triangle abc below: right triangle abc has a right angle at b. segment bd meets segment ac at a right angle. a student made the following chart to prove that ab2 + bc2 = ac2: statement justification 1. triangle abc is similar to triangle bdc 1. angle abc = angle bdc and angle bca = angle dcb 2. bc2 = ac x dc 2. bc ÷ dc = ac ÷ bc because triangle abc is similar to triangle bdc 3. triangle abc is similar to triangle adb 3. angle abc = angle adb and angle bac = angle dab 4. ab2 = ac x ad 4. ab ÷ ad = ab ÷ ac because triangle abc is similar to triangle abd 5. ab2 + bc2 = ac x ad + ac x dc = ac (ad + dc) 5. adding statement 2 and statement 4 6. ab2 + bc2 = ac2 6. ad + dc = ac what is the flaw in the student's proof?