Jose and jill are selling pies for a school fundraiser. customers can buy cherry pies and lemon meringue pies. jose sold 17 cherry pies and 14 lemon meringue for a total of $321. jill sold 9 cherry pies and 5 lemon meringue pies for a total of $141. find the cost of one cherry pie and one lemon meringue pie.

Cost of one cherry pie is $ 9 and cost of one lemon meringue is $ 12

Let "c" be the cost of one cherry pie

Let "m" be the cost of one lemon meringue

Given that Jose sold 17 cherry pies and 14 lemon meringue for a total of $321

We can frame a equation as:

17 cherry pies x cost of one cherry pie + 14 lemon meringue x cost of one lemon meringue = $ 321

17c + 14m = 321 ------- eqn 1

Jill sold 9 cherry pies and 5 lemon meringue pies for a total of $141

9 cherry pies x cost of one cherry pie + 5 lemon meringue x  cost of one lemon meringue = $ 141

9c + 5m = 141  -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "c" and "m"

Multiply eqn 1 by 5

85c + 70m = 1605 ----- eqn 3

Multiply eqn 2 by 14

126c + 70m = 1974  ------- eqn 4

Subtract eqn 3 from eqn 4

126c + 70m = 1974

85c + 70m = 1605

(-) -------------------

41c = 369

Substitute c = 9 in eqn 1

17c + 14m = 321

17(9) + 14m = 321

14m = 369 - 153

14m = 168

Thus the cost of one cherry pie is $ 9 and cost of one lemon meringue is $ 12

fourth month

step-by-step explanation:

it is the one with the most keychains.

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)