Solve the equation
3|2x-1|+2=17

the solutions are {-2, 3}

Step-by-step explanation:

First combine the constants 2 and 17:

3|2x-1|+2=17 => 3|2x - 1| = 15

Next, divide both sides by 3.  We get:

3|2x - 1| = 15 => |2x - 1| = 5

We want to solve for x, so divide all three terms by 2 as follows:

|x - 1/2| = 5/2

This equation has two solutions.  We regard 1/2 as the "center."  The equation tells us that x is either 5/2 greater than this 1/2 or 5/2 smaller:

x = 1/2 + 5/2 = 6/2,  or  x = 3

and:

x = 1/2 - 5/2 = -4/2 = -2

Thus, the solutions are {-2, 3}

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

idk this answer sorry cant on this one.

step-by-step explanation: