Asa

given that 6 > –2, which statements are true? check all that apply.

(2)(6) > (–2)(2)

6/2 < -2/2

(–2)(6) > (–2)(–2)

6/-2 < -2/-2

(2)(6) < (–2)(2)

6/2 > -2/2

The Statements which are true are:

(2)(6) > (–2)(2)

6/-2 < -2/-2

6/2 > -2/2

Step-by-step explanation:

Given:

6 > –2

We need to check all options which are true,

Hence we will check for all 1 by 1.

(2)(6) > (–2)(2)

It means that when 2 is multiplied on both side we get the value as

12 > -4

Since 12 is greater than -4.

Hence this statement is true.

6/2 < -2/2

It means that when 2 is divided on both side we get the value as

3 < -1

Since 3 is greater than -1.

Hence this statement is false.

(–2)(6) > (–2)(–2)

It means that when -2 is multiplied on both side we get the value as

-12 > 4

Since -12 is less than 4.

Hence this statement is false.

6/-2 < -2/-2

It means that when -2 is divided on both side we get the value as

-3 < 1

Since -3 is lesser than 1.

Hence this statement is true.

5) (2)(6) < (–2)(2)

It means that when 2 is multiplied on both side we get the value as

12 < -4

Since 12 is greater than -4.

Hence this statement is False.

6/2 > -2/2

It means that when 2 is divided on both side we get the value as

3 > -1

Since 3 is greater than -1.

Hence this statement is True.

to find the total number of combinations, multiply the quantity of each item by each other:

2 pairs of shoes x 3 pairs of shorts = 6 different combinations.

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: