Two friends, karen and jodi, work different shifts for the same ambulance service. they wonder if the different shifts average different numbers of calls. looking at past records, karen determines from a random sample of 35 shifts that she had a mean of 5.2 calls per shift. she knows that the population standard deviation for her shift is 1.3 calls. jodi calculates from a random sample of 34 shifts that her mean was 4.8 calls per shift. she knows that the population standard deviation for her shift is 1.2 calls. test the claim that there is a difference between the mean numbers of calls for the two shifts at the 0.05 level of significance.

(c) find the critical value.

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )

the above table 1 will calculate the population size (n) after a certain length of time (t). all you need to do is plug in the initial population number (no), the growth rate (r) and the length of time (t). the constant (e) is already entered into the equation. it stands for the base of the natural logarithms (approximately 2.71828). growth rate (r) and time (t) must be expressed in the same unit of time, such as years, days, hours or minutes. for humans, population growth rate is based on one year. if a population of people grew from 1000 to 1040 in one year, then the percent increase or annual growth rate is 40/1000 x 100 = 4 percent.

step-by-step explanation:

no its the same as every other grade

step-by-step explanation: