A95% confidence interval for the population proportion of townspeople that are in favor of the proposal is a (.86, .92). if there had been 1035 townspeople present at the meeting and 921 of those 1035 had been in favor of the proposal, what would happen to this interval?

921 of those 1035 people in the meeting had been in favor of the proposal confirms the 95% confidence interval (.86, .92)

Step-by-step explanation:

95% confidence interval for the population proportion of townspeople that are in favor of the proposal is a (.86, .92) means that 95% of the time population proportion of townspeople that are in favor of the proposal falls between .86 and .92.

If 921 of those 1035 had been in favor of the proposal, then the proportion in the meeting who are in favor of the proposal is ≈ 0.89.

Since this value falls  within the confidence interval, this evidence confirms the confidence interval.

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function