Last week, 108 cars received parking violations in the main university parking lot. of these, 27 had unpaid parking tickets from a previous violation. assuming that last week was a random sample of all parking violators, find the 95 percent confidence interval for the percentage of parking violations that have prior unpaid parking tickets.

95 percent confidence interval

[0.208,0.29166]

Step-by-step explanation:

First we identificate the sample proportion p = 27 /108, and we find the 95 percent confidence interval for P(population proportion) in this context the parking violations that have prior unpaid parking tickets.

Then α = 0.05 and 1 - α/2 = 0.975

Thus

The 95 percent confidence interval is

[ p ± 1.96 ]

[0.25  ± 1.96 ]

[0.208,0.29166]

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step-by-step explanation:

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: