What does the law of cosines reduce to when dealing with a right triangle

Pythagoras Theorem

Step-by-step explanation:

For any triangle ABC, the law of cosine is given by

Now, let us suppose the triangle ABC is a right triangle having right angle at C.

Thus, C = 90°

Substituting this value in above formula

We know that cos 90°= 0

Thus, the equation becomes

We can see that it reduces to Pythagoras Theorem.

Hence, we can conclude that law of cosines reduce to Pythagoras Theorem when dealing with a right triangle

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

two? xd

step-by-step explanation: