Exhibit 10-3 a statistics teacher wants to see if there is any difference in the abilities of students enrolled in statistics today and those enrolled five years ago. final examination scores from a random sample of students enrolled today and from a random sample of students enrolled five years ago were selected. you are given the following information. today five years ago 82 88 σ2 112.5 54 n 45 36 refer to exhibit 10-3. the point estimate for the difference between the means of the two populations is group of answer choices

6

Step-by-step explanation:

According to the given formation , we have

                                            Today Five                 Years Ago

Sample mean                        

Variance ()              112                     24

Sample size (n)                         45                           36

We know that , the point estimate for the difference between the means of the two populations is the difference between the sample means .

Then, the point estimate for the difference between the means of the two populations is

Hence, the point estimate for the difference between the means of the two populations is 6 .

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.