In a lab experiment, a student is trying to apply the conservation of momentum. two identical balls, each with a mass of 1.0 kg.
roll toward each other and collide. the velocity is measured before and after each collision. the collected data is shown below. which trial shows the conservation of momentum in a closed system?

Trial- 2 shows the conservation of momentum in a closed system.

Step-by-step explanation:

Given: Mass of balls are

Conservation of momentum in a closed system occurs when momentum before collision is equal to momentum after collision.

Now, According to conservation of momentum.

Momentum before collision = Momentum after collision

We will plug each trial to this equation.

Trial 1

Trial 2

Trial 3

Trial 4

We can see only Trial 2 satisfies the princple of conservation of momentum. That is momentum before collison should equal to momentum after collision.

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.