Acandy man manufacture wishes to mix two candies as a sales promotion when candy sells for $3per pound in other cells for $1.75 per pound the manufacture which is to have 1000 lbs of a mixture and stir the mixture for $2.35 per lbs how many pounds of each candy should be used in the mixture

Step-by-step explanation:

System Of Two Linear Equations

A system of two linear equations is given as

We must find the values of x and y who make both equations comply, i.e. they become identities

The question talks about one candy who sells for $3 per pound and others who sells for $1.75 per pound. Let's call x and y the pounds of each candy that must be used in a mixture with the conditions that:

We form the system with both conditions

Multiplying the second equation by 4

Multiplying the first equation by -7

Adding both equations

Using the relation

We solve for y

The solution is

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0