Because these are inequalities, you're not going to get only one ordered pair (ie, just one x-value & just one y-value) that satisfies them. What you can at least do is solve for y for both of them to graph them and see what you're dealing with. If we do this, we get the following for the inequalities, respectively:
y > 3x - 5
y ≥ -3x + 5
Graph them like you normally would equations, except the first one will get a dotted line because it doesn't have the "and equal to" part of the symbol like the second one does.
Next pick an ordered pair on one side of the 1st graph that is easy to plug in for the x & y, like (0,0). You should get 0>5. If this is true, then shade that entire side of the graph because all of those points will satisfy the inequality.
Do the same for the 2nd graph, plug in (0,0). You should get 0≥5. Is this true? No, so you shade the other side of the graph.
When you do all this, you should get an area in the shape of a large V that is shaded in for all of the ordered pairs that make both inequalities true.
TL;DR Your question doesn't make much sense, so I showed you how to graph them.
Maybe you want to know where they intersect? If that's the case, treat them like equations whose lines intersect. If we have
y = 3x - 5
y = -3x + 5
You can set the two right sides equal to each other (because they're both equal to y) and then just solve for x. Plug that number back in to either of the equations to get your y. That's where the two lines intersect.
Step-by-step explanation:
