Write the equation for the lines that passes through (-2,0) and (6,-4)

y=-1/2x-1

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-4-0)/(6-(-2))

m=-4/(6+2)

m=-4/8

simplify

m=-1/2

y-y1=m(x-x1)

y-0=-1/2(x-(-2))

y=-1/2(x+2)+0

y=-1/2x-2/2+0

y=-1/2x-1

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

“a term can be a signed number, a variable, or a constant multiplied by a + sign or j sign. in , the terms are 5x , 3y and 8. when a term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.” i hope this you.