How do i solve? the johnson twins were born seven years after their older sister. this year, the product of the three siblings' ages is exactly 2138 more than the sum of their ages. how old are the twins?

The twins are 11 years each and their older sister is 18 years.

Step-by-step explanation:

Let represent the age of one of the boys as x and that of the older sister as y.

The boys were born 7 years after their older sister can be represented as

Y = x + 7

This year, the product of the three siblings' ages is exactly 2138 more than the sum of their ages.

This can be represented as; x × x × y= 2138 + x + x + y

X^2 × y = 2138 + 2x + y….......(eqn 1)

Recall that Y = x + 7

Subs Y into eqn 1

X^2( x+7) = 2138 + 2x + x+7

X^3 +7x^2 - 3x - 2145 = 0

Solving this polynomial

X= 11 and y = 18.

The ages of the twins are 11 years each

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!