Afarmer feeds her four horses 64 bales of hay each week. how many bales of hay would the farmer need in order to feed six horses for a week?

In this question, we're trying to find how many bales of hay the farmer needs to get in order to feed 6 horses

First, we would need to find how many bales of hay each horse eats.

Find this by dividing 64 by 4

64 ÷ 4 = 16

We now know that each horse eats 16 bales of hay

Now, multiply 16 by 6 in order to find how many bales of hay the farmer needs to get to feed 6 horses.

16 × 6 = 96

Therefore, the farmer needs to get 96 bales of hay in order to feed 6 horses.

96 bales of hay

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .