What is the equation of the line that passes through the points (3,-2) and (6,3)? put your answer in full reduced form

Step-by-step explanation:

From the coordinate geometry, equation of line that passes through two coordinates will be

y-y1 ={(y2-y1)/x2-x1)}(x-x2) where x1=3,y1= -2, x2 =6, y2 = 3. therefore substitute for the values

y-(-2) ={ 3-(-2)/6-3} x (x-6)

y+2 = 3+2/3 x (x-6)

y+2 =5/3(x-6) multiply both side by 3,

3(y+2) = 5(x-6)

3y+6 =5x-30

3y = 5x -30 -6

3y = 5x - 36. Therefore the equation of the line is

3y = 5x - 36.

took the test it's 94

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option