Country motorbikes incorporated finds that it costs $400 to produce each motorbike, and that fixed costs are $1600 per day. the price function is p(x) = 700 − 5x, where p is the price (in dollars) at which exactly x motorbikes will be sold. find the quantity country motorbikes should produce and the price it should charge to maximize profit. also find the maximum profit. my equation for profit keeps on giving me a wrong answerquantity = 30price = 550profit = ?

30units,2900

Step-by-step explanation:

Given that Country Motorbikes Incorporated finds that it costs $400 to produce each motorbike, and that fixed costs are $1600 per day.

The price function is p(x) = 700 − 5x, where p is the price (in dollars) at which exactly x motorbikes will be sold.

If x units are produced and sold we have

Costs for x units = variable costs *x +Fixed costs

Sales revenue = no of units sold * price =

Profit funciton = P(x) = Sales revenue - Total cost

=

To get maximum profit we use derivative test I derivative =0 and II derivative =negative

Producing 30 units will maximize the profit.

Max profit

=P(30) = 2900

y=1/4x-4

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!