On a hot summer day 609 people used the public pool the daily price for children is 1.50 and 2.00 for adults at the end of the day the receipt for admission totaled 1061.50 how many adult and how many children were at the pool that day

The number of children at the pool that day is 313

The number of adults at the pool that day is 296

Step-by-step explanation:

Given as :

The Total number of people were using public pool = 609

The Total admission receipt collected at the day end = $1061.50

The entry price for children = $1.50

The entry price for adults = $2.00

Let The total number of children in the pool = c

And The total number of adults in the pool = a

Now, According to question

The Total number of people were using public pool =  The total number of children in the pool + The total number of adults in the pool

or, c + a = 609                 ...........1

And

The Total admission receipt collected at the day end = The entry price for children × The total number of children in the pool + The entry price for adults × The total number of adults in the pool

or, $1.50 × c + $2.00 × a = $1061.50

I.e 1.50 c + 2 a = 1061.50             ............2

Now, Solving equation 1 and 2

2 × (c + a) - (1.50 c + 2 a) = 2 × 609 - 1061.50

Or, 2 c + 2 a - 1.50 c - 2 a = 1218 - 1061.50

Or, (2 c - 1.50 c) + (2 a - 2 a) = 156.5

Or, 0.5 c + 0 = 156.5

∴  c =

I.e c = 313

So, The number of children at the pool = c = 313

Now,

Put The value of c in eq 1

I.e ,c + a = 609  

Or, 313 + a = 609

Or, a = 609 - 313

∴   a = 296

So, The number of adults at the pool = a = 296

Hence The number of children at the pool that day is 313

And The number of adults at the pool that day is 296     Answer

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: