What is an equation for the linear function whose graph contains the points (2, 5) and (3, 0)?
enter your answers in the boxes.
y - __ = __ (x - 2)

y - 5  = (-5)(x -2) is the required line equation.

The first blank = 5

Second blank = (-5)

Step-by-step explanation:

Here, the two points are given as A(2,5) and B (3,0).

SLOPE of a line with points (a,b) and (c,d) is given as

Now, here the Slope of line AB is given as  

or, the slope of line AB = -5

by POINT SLOPE FORMULA:

The equation of line with point (x0,y0) and slope m is given as

y - y0 = m (x -x0)

So, here the point (2,5) and slope (-5), the equation of line is given as:

y - 5  = (-5)(x -2)

Now, comparing the above line equation with :  y - __ = __ (x - 2)

We get :  The first blank = (5)

                Second blank = (-5)

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

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