In the past, 35% of the students at abc university were in the business college, 35% of the students were in the liberal arts college, and 30% of the students were in the education college. to see whether or not the proportions have changed, a sample of 300 students was taken. ninety of the sample students are in the business college, 120 are in the liberal arts college, and 90 are in the education college.

1. this problem is an example of a
a. normally distributed variable
b. test for independence
c. poisson distributed variable
d. multinomial population ans: d

2. the expected frequency for the business college is
a. 0.3
b. 0.35
c. 90
d. 105 ans: d

3. the calculated value for the test statistic equals
a. 0.01
b. 0.75
c. 4.29
d. 4.38 ans: c

4. the hypothesis is to be tested at the 5% level of significance. the critical value from the table equals
a. 1.645
b. 1.96
c. 5.991
d. 7.815 ans: c

5. the p-value is
a. greater than 0.1
b. between 0.05 and 0.1
c. between 0.025 and 0.05
d. between 0.01 and .025 ans: a

6. the conclusion of the test is that the
a. proportions have changed significantly
b. proportions have not changed significantly
c. test is inconclusive
d. none of these alternatives is correct.

answer: you need the equation in the question so i can answer it

step-by-step explanation:

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497