Given x5y" + 2x4 y' + (1-x3) y = 0 (1-1) where y' and y" are respectively and . a) does this equation have regular or irregular singular points? b) respectively, use 1/z, and to replace x, and so that equation (1-1) becomes f(z, , ) = 0; explain that when x is sufficiently large, letting x = 1/z can be a good approach. c) find the solution of your new equation f(z, , ) = 0