In a poll taken in december 2012, gallup asked 1006 national adults whether they were baseball fans: 48% said they were. almost five years earlier, in february 2008, only 35% of a similar-size sample had reported being baseball fans. a) define p and p (what proportions are we looking at? this questions is not asking the value of p) b) find the margin of error for the 2012 poll if we want 90% confidence in our estimate of the percent of national adults who are baseball fans. c) explain what that margin of error means. d) if we wanted to be 99% confident would the margin of error be larger or smaller. e) find that margin of error

0.0259,0.0406

Step-by-step explanation:

Given that in a poll taken in December 2012, Gallup asked 1006 national adults whether they were baseball fans: 48% said they were. Almost five years earlier, in February 2008, only 35% of a similar-size sample had reported being baseball fans.

a) p is the proportion of national adults who are baseball fans.

b) For 2012 poll, p=0.48

Std error =

Margin of error at 90% = 1.645 * std error

= 0.0259

c) Margin of error is the admissible limit on either side of the mean where the sample mean can lie

d) Margin of error would be larger for 99% because critical value 2.58 >1.645

e) Margin of error 99% =

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6