the safe load, l, of a wooden beam supported at both ends varies jointly as the width, w, the square of the depth, d, and inversely as the length, l. a wooden beam 6in. wide, 9in. deep, and 12ft long holds up 1090lb. what load would a beam 5in. wide, 4in. deep and 17ft long of the same material support? (round off your answer to the nearest pound.)

Safe Load is 127 lb.

Step-by-step explanation:

Given:

Load (L) = 1090 lb.

width(w) = 6 in.

depth (d) = 9 in.

length (l) = 12 ft.

Since all other units are in inches and unit of length is in feet, So we will convert foot into inches we get;

1 feet = 12 inches

12 feet =

Hence length(l)= 144 in.

Now also Given

Load varies directly with width and square of depth and inversely with length.

Hence we can say that;

L∝

Hence where k is constant.

Now Substituting the given values we will find the value of k we get;

Also Given:

width(w) = 5 in.

depth(d) = 4 in.

length(l) = 17 ft.

1 ft. = 12 in.

17 ft =

Hence length(l) = 204 in.

k = 322.96

We need to find the load beam(L);

Substituting new values we get;

Rounding the load in nearest pound we get;

Load beam(L) = 127 lb

Hence Safe  Load is 127 lb.

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: