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what is the equation of the line that passes through (3,-8) and has a slope of 0?

y= - 2

Step-by-step explanation:

You want to find the equation for a line that passes through the point (3,-2) and has a slope of 0.

First of all, remember what the equation of a line is:

y = mx+b

Where:  

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 0. So you can right away fill in the equation for a line somewhat to read:

y=0x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(3,-2). When x of the line is 3, y of the line must be -2.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (3,-2).

So, why not plug in for x the number 3 and for y the number -2? This will allow us to solve for b for the particular line that passes through the point you gave!.

(3,-2). y=mx+b or -2=0 × 3+b, or solving for b: b=-2-(0)(3). b=-2.

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