The distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. what does the average rate of change of d(t) from t = 3 to t = 6 represent?

Average Rate of change of d(t) is 11.43

Step-by-step explanation:

Given:

d(t) = 4.9 t²

where d(t) gives distance covered by coin in time t.

To find: The Average Rate of change of d(t) from t = 3 to t = 6.

We know that Average rate of change, A of f(x) =

here, a= 6 and b = 3

So, Average rate of change =

                                               =

                                               =

                                               =

                                               =

                                               =

Therefore, Average Rate of change of d(t) is 11.43

4 puzzles in 3 hours

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: