Small sample mean problem. a study was done to determine the effect of vitamin supplements for the mother on the birth weight of babies. the sample size was 17. all the women in the study regularly visited a doctor during their pregnancy. the data below show the summary statistics and a stem and leaf plot of the birth weight of the 17 babies. weight is in kilograms (kg). 3.761 3.730 0.531 0.729 19.380 17 stem leaf mean median variance std dev cv count 2 47 302 22 39 43 352 68 73 73 4 09 13 33 37 447 68 5 14 in kg, stem is whole number 2147 is 2.47 the average weight of all babies from women receiving regular care during pregnancy in the region of the study was 3.40 kg. (treat this as if it is the population value). you are asked to conduct a test to see if the sample mean from the mothers given vitamin supplements is different from the regional average of 3.40. use alpha .05. what is the test statistic?

step-by-step explanation:

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w

cause it equals more