The cdc has determined that a person has a 90% probability of getting measles if they are exposed to someone with the disease. suppose you live in brooklyn and the measles outbreak has caused everyone be exposext in your tight social circle of four friends (in addition to you), what is the theoretical probability that at least one of you five individuals contracts the measles virus? show how you know.

Step-by-step explanation:

The probability at least one contracts the virus is the opposite (1 minus) the probability that none contracts the virus.

Using binomial probability:

P = nCr pʳ (1−p)ⁿ⁻ʳ

P(none) = ₅C₀ (0.9)⁰ (1−0.9)⁵⁻⁰

P(none) = (0.1)⁵

P(none) = 0.00001

P(at least one) = 1 − P(none)

P(at least one) = 1 − 0.00001

P(at least one) = 0.99999

There is a 99.999% probability that at least one of five individuals contracts the virus.

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it